Wikisource has many: https://en.wikisource.org/wiki/Category:Cookbooks

Les Gueaux

It’s the year of the desktop inside Linux

Cats

Install the package kdegraphics-thumbnailers, and then depending on the file manager you may have to enable previews, e.g. in Dolphin > Configure Dolphin > Interface > Previews.

Long time ago I wrote down a lot of movies to watch. I was able to watch many, but that one is the oldest in my list that I couldn’t find. Oh, and thanks for the pointer!

Les Diaboliques (1955)

Couldn’t find it anywhere, so it’s still at the top of the list.

Is this a joke abour East Slavic languages?

This is what happens if you let criminals choose the sentence

Which country?

But why are the boys not colored with a picture of their surroundings?

aA1!:-)atheism2.71828Humberto

Because it’s a visitor center and not a crater center, duh.

Too uniformly distributed

The recline is needed for overnight flights. On short haul, it’s unnecessary indeed. I think some airline have ordered seats without recline already.

https://en.wikipedia.org/wiki/Portal:Current_events

Only very short summaries of what happened, linked to Wikipedia article for more reading.

In this Lemmy community?

This is not the price to access a paper. This is the price to publish one paper.

It really depends on the country. France and Belgium, as you wrote. Germany, they expect a tip and look at you angry if you don’t. Italy, they add a service charge at the end that is nowhete advertised. Turkey, they invent a random price at the end, complaints only taken if you’re local. (I’m slightly exaggerating)

You want an answer?

So you’ve probably learned that if u is an eigenvector, then multiplying u by any scalar gives you another eigenvector with the same eigenvalue. That means that the set of all a*u where a is any scalar forms a 1-dimensional space (a line if this is a real vector space). This is an eigenspace of dimension one. The full definition of an eigenspace is as the set of all eigenvectors of a given eigenvalue. Now, if an eigenvalue has multiple independent eigenvectors, then the set of all eigenvectors for that eigenvalue is is still a linear space, but of dimension more than one. So for a real vector space, if an eigenvalue has two sets of independent eigenvectors, its eigenspace will be a 2-dimensional plane.

That’s pretty much it.